Area Info
Calendar
Area Nets
Area Repeater List
Forums
New posts
Search forums
What's new
New posts
New media
New media comments
New resources
New profile posts
Latest activity
Media
New media
New comments
Search media
Resources
Latest reviews
Search resources
Exam Prep
Log in
Register
What's new
Search
Search
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Install the app
Install
Forums
Public Forums
Articles
Tech Talk "Resister Network Answers" By Jim Purvis WA7HRG
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Message
<blockquote data-quote="KY4TRK" data-source="post: 12036" data-attributes="member: 2"><p><strong>Archive</strong> 2010</p><p></p><p><strong><em>Tech Talk</em></strong></p><p></p><p>By Jim Purvis WA7HRG</p><p></p><p></p><p></p><p>In lasts months column I presented some explanation of Ohms Law and how it related to Voltages, Current and Power in a circuit. Along with that was a simple resister network and a challenge to calculate the voltage, current, and power for each component. And as promised, here are the answers.</p><p></p><p></p><p></p><p><strong>Answers to the Ohms Law Challenge</strong></p><p><strong></strong></p><p><strong><strong><strong>1</strong></strong></strong></p><p></p><p>Total Equivalent Resistance = R1+ <em>1</em> + <strong><em>1</em></strong></p><p></p><p>R2 R3+R4</p><p></p><p>=1K + <strong><strong><strong>1</strong></strong></strong></p><p></p><p>.0002+.0005</p><p></p><p>=1K+1428.5</p><p></p><p>=2,428.5 ohms</p><p></p><p></p><p></p><p>Total Current (I) = <strong>E</strong> E=13.5-Drop across D1</p><p></p><p>Rt</p><p></p><p>= <strong>12.8</strong></p><p></p><p>2428.5</p><p></p><p>= .0052 A</p><p></p><p></p><p></p><p>Total Power Dissipated = IxE</p><p></p><p>= .0052x12.8</p><p></p><p>= .0665 Watts</p><p></p><p></p><p></p><p>Total current through D1 = Total ckt current</p><p></p><p>= .0052 A</p><p></p><p></p><p></p><p>Power Dissipated by D1 = IxE</p><p></p><p>= .0052x.7</p><p></p><p>= .00364 Watts</p><p></p><p></p><p></p><p>VR1 = IxR IR1 = Total I PR1 = IxE</p><p></p><p>= .0052x1K = .0052A = .0052x5.2</p><p></p><p>= 5.2V = .02704 Watts</p><p></p><p></p><p></p><p>VR2 = (13.5-V-drop D1)-VR1 IR2 = E/R PR2 = IxE</p><p></p><p>= (13.5-.7)-5.2 = 7.6/5K = .00125x7.6</p><p></p><p>= 7.6 V = .00152 A = .001155 Watts</p><p></p><p></p><p></p><p>VR3,R4 = Vr2/2 IR3,R4 = E/R PR3,R4 = IxE</p><p></p><p>= 7.6/2 = 3.8/1K =.0038x3.8</p><p></p><p>= 3.8 V = .0038 A = .01444 Watts</p></blockquote><p></p>
[QUOTE="KY4TRK, post: 12036, member: 2"] [B]Archive[/B] 2010 [B][I]Tech Talk[/I][/B] By Jim Purvis WA7HRG In lasts months column I presented some explanation of Ohms Law and how it related to Voltages, Current and Power in a circuit. Along with that was a simple resister network and a challenge to calculate the voltage, current, and power for each component. And as promised, here are the answers. [B]Answers to the Ohms Law Challenge [B][B]1[/B][/B][/B] Total Equivalent Resistance = R1+ [I]1[/I] + [B][I]1[/I][/B] R2 R3+R4 =1K + [B][B][B]1[/B][/B][/B] .0002+.0005 =1K+1428.5 =2,428.5 ohms Total Current (I) = [B]E[/B] E=13.5-Drop across D1 Rt = [B]12.8[/B] 2428.5 = .0052 A Total Power Dissipated = IxE = .0052x12.8 = .0665 Watts Total current through D1 = Total ckt current = .0052 A Power Dissipated by D1 = IxE = .0052x.7 = .00364 Watts VR1 = IxR IR1 = Total I PR1 = IxE = .0052x1K = .0052A = .0052x5.2 = 5.2V = .02704 Watts VR2 = (13.5-V-drop D1)-VR1 IR2 = E/R PR2 = IxE = (13.5-.7)-5.2 = 7.6/5K = .00125x7.6 = 7.6 V = .00152 A = .001155 Watts VR3,R4 = Vr2/2 IR3,R4 = E/R PR3,R4 = IxE = 7.6/2 = 3.8/1K =.0038x3.8 = 3.8 V = .0038 A = .01444 Watts [/QUOTE]
Insert quotes…
Verification
What is our club's callsign?
Post reply
Forums
Public Forums
Articles
Tech Talk "Resister Network Answers" By Jim Purvis WA7HRG
Top
